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In Mathematics / Middle School | 2014-11-02

The crew on a fishing boat caught four fish weighing a total of 1092 pounds. The tarpon weighed twice as much as the amberjack, and the white marlin weighed twice as much as the tarpon. The weight of the tuna was 5 times the weight of the amberjack. How much did each fish weigh?

Asked by Anonymous

Answer (3)

x= weight of amberjack 2x= weight of tarpon 4x= weight of marlin 5x= weight of tuna
x + 2x + 4x + 5x= 1092 12x=1092 x= 91
Amberjack weighs 91 pounds Tarpon= 2 x 91 = 182 pounds Marlin= 4 x 91= 364 pounds Tuna = 5 x 91 = 455 pounds

Answered by RhysH | 2024-06-10

ta = tarpon am = amberjack wm = white marlin tu = tuna
ta + am + wm + tu = 1092 ta = 2 * am wm = 2 * ta = 4 * am tu = 5 * am
2 * am + 4 * am + 5 * am + am = 12 am = 1092 am = 91 ta = 2 * 91 = 182
etc...

Answered by eskilfogelstrom | 2024-06-10

The weights of the fish are: Amberjack: 68.25 pounds, Tarpon: 136.5 pounds, White Marlin: 546 pounds, Tuna: 341.25 pounds.
;

Answered by RhysH | 2024-09-27

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