p H = − l o g ∣ H 3 O + ∣ p H = − l o g 2.4 ∗ 1 0 − 5 = − ( l o g 2.4 + l o g 1 0 − 5 ) = − ( 0 , 38 − 5 ) = − ( − 4.62 ) p H = 4.62
The pH of the solution is 4.61. ;
The pH of a solution with a concentration of 2.4 × 1 0 − 5 molar H 3 O + is approximately 4.62. To find this, we used the formula p H = − log [ H 3 O + ] . The calculated pH value indicates a mildly acidic solution.
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