What is the missing exponent?

\[
(12^{-5})^2 / 12^{-4} = 12^{\_\_\_\_}
\]

1 2 − 4 ( 1 2 − 5 ) 2 ​ = 1 2 − 4 1 2 − 5 × 2 ​ = 1 2 − 4 1 2 − 10 ​ = 1 2 − 10 − ( − 4 ) = 1 2 − 10 + 4 = 1 2 − 6 A n s w er : − 6 ​

Answered by Anonymous | 2024-06-10

The missing exponent in the expression ( 1 2 − 5 ) 2 /1 2 − 4 = 1 2 ___ is − 6 . We find this by applying the power of a power rule and the quotient rule of exponents. So the answer is 1 2 − 6 .
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Answered by Anonymous | 2024-12-26