A motorcycle stunt driver zooms off the end of a cliff at a speed of 30 meters per second. If he lands after 0.75 seconds, what is the height of the cliff?

u = 30 m s − 1 t = 0.75 s a = 9.8 m s − 2 ( G r a v i t y ) s = ?
s = u t + 2 1 ​ a t 2 s = ( 30 ) ( 0.75 ) + 2 1 ​ ( 9.8 ) ( 0.75 ) 2 s = 22.5 + 2.75625 s = 25.25625
s = 25.3 m (3 sf)

Answered by ollieboyne | 2024-06-10

The height of the cliff from which the motorcycle stunt driver jumps is approximately 25.3 meters. This was calculated using the initial speed, the time in the air, and the acceleration due to gravity. By applying the equations of motion, we found the vertical distance fallen during the stunt.
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Answered by ollieboyne | 2024-10-31