p = 1.5atm ≈ 1519.88hPa V = 8.56L R = 83.1 [hPa L] / [mol K] T = 0°C =273K
pV = nRT |:RT
n = pV / RT
n = [1519.88hPa 8.56L] / [83.1 [hPa L] / [mol*K] * 273K] n ≈ 0.57mol
According to ideal gas law , there are 0.00565 number of **moles **of hydrogen present in the gas sample .
What is ideal gas law?
The ideal gas law is a equation which is applicable in a hypothetical state of an ideal gas.It is a combination of Boyle's law, Charle's law,Avogadro's law and Gay-Lussac's law . It is given as, PV=nRT where R= gas constant whose value is 8.314.The law has several limitations.Ideal gas law was proposed by Benoit Paul Emile Clapeyron in year 1834.It is a thermodynamic equation which has wide applications.
Gases which obey ideal gas law are difficult to exist.
Substituting the values as, P=1.5 atmospheres, V=8.56 L, R=8.314 ,T=0°C=273 K that is , n=PV/RT=1.5×8.56/8.314×273=0.00565 moles.
Thus, there are 0.00565 **moles **of hydrogen present in the gas sample .
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Using the ideal gas law, the number of moles of hydrogen gas present in the sample can be calculated to be approximately 0.573 moles. This is done by rearranging the gas law equation to solve for n and substituting the given values of pressure, volume, and temperature. Make sure to convert temperature to Kelvin and use the appropriate gas constant for the units used.
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