A bolt falls off an airplane high above the ground. How far does the bolt have to fall before its speed reaches 100 m/s (about 200 miles per hour)? Ignore air friction in your calculation.

We can use the equation vf (the final velocity) =vi (the initial velocity) +at (aceleration times time)
We know the final velocity 100m/s, the initial velocity 0, and the acceleration (gravity) 9.8m/s^2. So, 100=0+9.8t. t=100/9.8

Answered by Anonymous | 2024-06-10

The bolt have to **fall **500 m before its **speed **reaches 100m/s
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What is speed?
**Speed **is distance travelled by the object per unit time. Due to having no direction and only having magnitude, **speed **is a scalar quantity With SI unit meter/second.
Given parameters:
Initial **speed **of the ball: u = 0 m/s.
Final **speed **of the ball: v = 100 m/s.
Let; acceleration due to **gravity **is 10 m/s².
We have to find the distance **travelled **by the ball: s = ?
We know that;
v² = u² + 2gs
⇒ 100² = 0² + 2×10×s
⇒ s = 100×100/(2×10) m.
⇒s = 500 m.
So, the distance **travelled **by the ball is 500 m.
Learn more about **speed **here:
https://brainly.com/question/28224010
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Answered by triptivt3 | 2024-06-16

The bolt must fall 500 meters to reach a speed of 100 m/s, given that we ignore air friction and consider only the acceleration due to gravity. This is calculated using the kinematic equation relating speed, distance, and acceleration. The final result indicates that under these ideal conditions, the bolt accelerates by 10 m/s² until it reaches the specified speed.
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Answered by triptivt3 | 2024-12-26