Solve the inequalities:
\[ 8r - 5 > 6r - 1 \]
or
\[ 4 + 4r < 3r - 3 \]
Answer (3)
For the first inequality you add 5 to each to get 8r>6r+4, then subtract 6r from each to get 2r>4 and divide by 2 so for that part r>2... For the second equation subtract 4 from each side to get 4r<3r-7, then subtract 3r to get r<-7... When you put it all together you get 2
The two given inequality equations, when solved, yield the solutions 'r > 2' for the first **equation **and 'r < -7' for the second one. ;
The solutions for the inequalities are r > 2 for the first inequality and r < -7 for the second inequality.
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