The sum of two numbers is 92. Their difference is 20. Find the two numbers.

x+y =92 x -y =20 ------------ (subtract the y) 2x= 112 /2 /2 x=56 56+y=92 (substitute x with 56) -56 -56 y=36
x = 56 and y = 36

Answered by ohnoorim | 2024-06-10

The two numbers in question obtained by creating a system of equations are 56 and 36
Let the two numbers be : a and b

a + b = 92 ___(1)
a - b = 20.___(2)

From (2):

a = 20 + b. ____(3)

Substitute (3) into (1)
a + b = 92
20 + b + b = 92
20 + 2b = 92
2b = 92 - 20
2b = 72
b = 72/2
b = 36
From (3) :
a = 20 + 36
a = 56
Therefore, the two numbers are 56 and 36
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Answered by fichoh | 2024-06-15

The two numbers are 56 and 36. We found this by creating a system of equations based on their sum and difference. Using algebraic substitution, we solved for each number step-by-step.
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Answered by fichoh | 2024-10-01