Acceleration is sometimes expressed in multiples of [tex]g[/tex], where [tex]g = 9.8 \, \text{m/s}^2[/tex] is the acceleration due to gravity.

In a car crash, the car's velocity changes from [tex]30 \, \text{m/s}[/tex] to [tex]0 \, \text{m/s}[/tex] in [tex]0.15 \, \text{s}[/tex].

In terms of [tex]g[/tex], what is the acceleration of the car?

The acceleration of the car in terms of g will be equal to 20 g.
What is acceleration?
Acceleration can be demonstrated as changing the velocity of an object with respect to time. The acceleration of an object can be described as a vector quantity exhibiting both magnitude and direction . Acceleration can be expressed as the first derivative of the velocity of an object w.r.t. time.
The** average acceleration** can be calculated dom the difference in velocities divided by the change in time.
Acceleration = (Final velocity - Initial velocity)/ Time
The initial velocity of the given car, u = 30 m/s
The final velocity, v = 0 m/s
The time taken by car, t = 0.15 s
The** average acceleration** = (0- 30)/0.15 = -200 m/s²
In terms of g, acceleration of car = 200/9.8 = 20 g
Therefore, the acceleration of the car will be equal to 20 g where g is the acceleration due to gravity .
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Answered by sarbajitpanda | 2024-06-16

The acceleration of the car is approximately 20.41 g, indicating a rapid deceleration from an initial velocity of 30 m/s to 0 m/s in 0.15 seconds. This negative acceleration reflects the significant change in velocity during the crash. The calculation shows how to express the acceleration in terms of the standard gravitational acceleration g, which is 9.8 m/s².
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Answered by sarbajitpanda | 2024-09-04