124 minions can run fast, and 68 minions can jump high. Gru wants to make teams with the same number of minions who can run fast and the same number of minions who can jump high. What is the greatest number of teams Gru can make?

You divide the minions by the amount of teams there are I'm assuming that there are two so I will divide by two 124÷2=62 68÷2=34 If there are two teams, there are 62 minions who can run fast and 34 minions who can jump high on both teams.

Answered by Geekhawk | 2024-06-10

The greatest number of teams Gru can create such that each team has the same number of minions who can run fast and jump high is 4. This is obtained by finding the greatest common divisor (GCD) of 124 and 68, which is 4. ;

Answered by AliceB123 | 2024-06-18

Gru can make a total of 4 teams with the minions who can run fast and jump high. Each team will consist of 31 fast-running minions and 17 high-jumping minions. This is determined by finding the greatest common divisor of 124 and 68, which is 4.
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Answered by Geekhawk | 2025-02-20