f ( x ) = 2 x + b → l in e o n e 5 = 2 ∗ ( − 1 ) + b → l in e tw o 5 = − 2 + b → l in e t h ree 5 + 2 = b → l in e f o u r 7 = b
To solve for the variable b in the equation f ( x ) = 2 x + b given that f ( − 1 ) = 5 , we substitute − 1 into the equation. This yields the equation 5 = − 2 + b , leading to b = 7 . Thus, the equation becomes f ( x ) = 2 x + 7 .
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