Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 hours, and Car B traveled the distance in 4.5 hours. Car B traveled 5 mph slower than Car A.
How fast did Car B travel?
Answer (2)
x-5=speed of car B x = speed of car A
Distance = speed times time distances is equal so (x-5)(4.5)=(x)(4) 4.5x-22.5=4x multiply both sides by 2 to get rid of the decimals 9x-45=8x subtract 8x from both sides x-45=0 a add 45 to both sides and get x=45 speed of car A = 45 mph Speed of car B = 45-5 or 40 mph Speed of car B = 40 mph
Car B traveled at a speed of 40 mph. This was determined by solving for the speed of Car A, which was found to be 45 mph, while knowing that Car B is 5 mph slower. Thus, the final speed of Car B is 40 mph.
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