How do you solve the following system of equations?

1. \(2x - y = 17\)
2. \(x - y = 10\)

another way to do it is 2x-y=17 x-y=10, x=10+y substitute x=10+y for x in 2x-y=17 and get 2(10+y)-y=17 20+2y-y=17 20+y=17 subtract 20 from both sides y=-3 subsitute y=-3 into equation x-y=10 x-(-3)=10 x+3=10 subtract 3 from both sides x=7 or subsitute into 2x-y=17 2x-(-3)=17 2x+3=17 subtract 3 from both sides 2x=14 divide both sides by two x=7

Answered by apologiabiology | 2024-06-10

Multiply (x-y=10) by -2. You will get -2x+2y=-20.then multiply by 1 2x-y=17 that give u the same thing. Cross out the -2x and 2x then subtract 2y by y which will leave u with y and subtract -20 by 17 that will leave with -3 . So y= -3

Answered by Anna2356 | 2024-06-10

To solve the equations 2 x − y = 17 and x − y = 10 , we can express y from the second equation and substitute it into the first equation, resulting in x = 7 and y = − 3 . Therefore, the solution is ( 7 , − 3 ) . Both original equations are satisfied with these values.
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Answered by apologiabiology | 2024-12-26