62 ⋅ 45 = ( 60 + 2 ) ⋅ ( 40 + 5 ) = 60 ⋅ 40 + 60 ⋅ 5 + 2 ⋅ 40 + 2 ⋅ 5 = = 2400 + 300 + 80 + 10 = 2 , 790 A n s . t h e p a r t ia l p ro d u c t s : 2400 , 300 , 80 an d 10.
The partial products of 62 and 45 are obtained by breaking the numbers into their place values and multiplying each part. The calculated partial products are 2400, 300, 80, and 10, resulting in a total product of 2790. This method helps in better understanding multiplication through the use of partial sums.
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