Atomic weight of LiBr = 86.845
Using the formula Concentration = moles/Liters
Converting grams to mol:
100gLiBr/86.845 = 1.1515 mol
Plugging values into the formula:
1.15 mol LiBr /4M concentration = 0.2875 L
You can prepare approximately 0.2878 liters of a 4M lithium bromide solution from 100 grams of LiBr by first calculating the moles of LiBr and then using the molarity formula to find the volume of the solution. The molar mass of LiBr is 86.84 g/mol, allowing us to find that 100 grams equals about 1.151 moles. Finally, dividing the number of moles by the molarity gives us the volume of solution in liters.
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