Francisco's game involves 3 green, 2 yellow, 4 red, and 3 black marbles. If he randomly draws three marbles from the bag, without replacement, what is the probability that he will draw a yellow, a red, and then a black marble?
Answer (3)
(2/12) X (4/11) X (3/10) = .018
( 2/12) X (4/11) X (3/10) = .018
The probability that Francisco will draw a yellow marble, followed by a red marble, and then a black marble, is 55 1 . This calculation was done by considering the total number of each colored marble and adjusting the total after each draw. Thus, the probability is the product of the probabilities of drawing each marble in sequence.
;
