Which equation supports the given conjecture?

The sum of the squares of two consecutive integers is an odd integer.

A. \((2^2 + 3^2)\)

B. \(3^2 + 5^2 = 34\)

C. \(4^2 + 5^2 = 41\)

D. \(5^2 + 6^2 = 61\)

the first part says the sum of the squares of two consecutive integers or in other words (x)(x)+(x+1)(x+1) so we can cross out A because 2 and 3 are prime numbers (no factors) we can cross out all the others because the square root of 52 is not an integer so any equation with 52 in it does not satisfy the requirement. so none of them are corect. additionally, some of the equations are obviously false such as 52+62=61

Answered by apologiabiology | 2024-06-10

The verified answer is wrong the correct answer is d 5 squared plus 6 squared. Because the question is asking for two consecutive integers and it wants an odd integer therefor d is the correct answer because it has to squared consecutive integers and an odd answer.
Hope i helped Mark as brainliest

Answered by brianisshort | 2024-06-11

The conjecture that the sum of the squares of two consecutive integers is an odd integer is supported by options A, C, and D, all resulting in odd integers. However, option D, displaying consecutive integers 5 and 6, provides the best example. Thus, the answer is D: 5 2 + 6 2 = 61 supports the conjecture.
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Answered by apologiabiology | 2024-12-26