What are 5 consecutive even integers that add up to 0?

2 n + 2 n + 2 + 2 n + 4 + 2 n + 6 + 2 n + 8 = 0 10 n + 20 = 0 10 n = − 20 n = − 2 2 n = − 4 2 n + 2 = − 2 2 n + 4 = 0 2 n + 6 = 2 2 n + 8 = 4 { − 4 , − 2 , 0 , 2 , 4 } ​

Answered by konrad509 | 2024-06-10

2 a , 2 a + 2 , 2 a + 4 , 2 a + 6 , 2 a + 8 2 a + 2 a + 2 + 2 a + 4 + 2 a + 6 + 2 a + 8 = 0 10 a + 20 = 0 ∣ s u b t r a c t 20 10 a = − 20 ∣ d i v i d e b y 10 a = − 2 N u m ers a re : − 2 , 0 , 2 , 4 , 6.

Answered by luana | 2024-06-10

The five consecutive even integers that add up to 0 are -4, -2, 0, 2, and 4. This is derived from expressing the integers in terms of the first integer and solving the resulting equation. The calculation confirms that their sum equals 0.
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Answered by Anonymous | 2025-05-01