H₂:
M=2g/mol m=10g
n = m/M = 10g/2g/mol = 5mol
O₂:
M = 32g/mol m = 80g
n = m/M = 80g/32g/mol = 2,5mol
2H₂ + O₂ ⇒ 2H₂O 2mol : 1mol : 2mol 5mol : 2,5mol : 5mol 10g : 80g : 10g+80g=90g
B
When 10.0 grams of hydrogen reacts with 80.0 grams of oxygen, 90.0 grams of water is produced. The reaction follows the stoichiometric ratios from the balanced equation. Therefore, the correct answer is B. 90.0 grams.
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