How many molecules are there in 79 g of [tex]\text{Fe}_2\text{O}_3[/tex]? How many atoms are in this amount?
Answer (2)
Molar mass of iron(III) oxide is 160g/mol
160g ----------- of iron(III) oxide is ---------------- 6.02*10²³molecules 79g ----------- of iron(III) oxide is ---------------- x
x = [6.02 10²³ 79g]/160g ≈ 2.97*10²³ molecules
In 79 g of F e 2 O 3 , there are approximately 2.97 × 1 0 23 molecules and about 1.485 × 1 0 24 atoms. The calculations involve finding the molar mass of F e 2 O 3 and using it to determine the moles, then applying Avogadro's number. Finally, the total number of atoms is calculated based on the number of molecules.
;
