48 dm\(^3\) of a gas has a mass of 262 g.
a. How many moles is this?
b. What is the \(M_r\)?
c. What must this element be?
Answer (3)
n = V 0 V V = 48 d m 3 V 0 = 22.4 m o l d m 3 n = 22.4 m o l d m 3 48 d m 3 ≈ 2 m o l n = M r m ⇒ M r = n m m = 262 g n = 2 m o l M r = 2 m o l 262 g = 131 m o l g
This element must be xenon.
The **number **of moles is 1.49 and the molar mass is 176.124 g/mol. ;
The number of moles of the gas is approximately 2.14 mol, and its molar mass is about 123 g/mol. The gas is likely xenon or a similar element. This gas has a significant molar mass, indicating it is a heavy noble gas or a related compound.
;
