Write the balanced equation for the neutralization reaction between HI and Ba(OH)₂ in an aqueous solution. Include physical states.
Answer (3)
Acid + Base = Salt + Water
2HI (Acid) + Ba(OH)2 (Base) = BaI2 + 2H2O
Hope this makes sense and helps :)
To write the balanced equation for the neutralization reaction between HI and Ba(OH)2 in aqueous solution, we first identify the reactants and the products. Hydroiodic acid (HI) is a strong acid, and barium hydroxide (Ba(OH)2) is a strong base, thus the reaction will produce water (H2O) and barium iodide (BaI2). The complete balanced equation along with physical states will be:
2 HI(aq) + Ba(OH)2(aq) → 2 H2O(l) + BaI2(aq)
Moreover, if you are looking for the net ionic equation representing the neutralization of any strong acid with an ionic hydroxide, we consider that HI will dissociate into H+ and I− ions, and Ba(OH)2 into Ba2+ and OH− ions in solution. Since HI and Ba(OH)2 are both strong electrolytes, the net ionic equation only includes the hydrogen ions and hydroxide ions:
H+(aq) + OH−(aq) → H2O(l)
The balanced equation for the neutralization reaction between HI and Ba(OH)₂ is 2 HI (aq) + Ba(OH)₂ (aq) → BaI₂ (aq) + 2 H₂O (l). This reflects the conversion of hydroiodic acid and barium hydroxide into barium iodide and water. All reactants and products are shown with their physical states included.
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