What is the percent mass/volume of a sodium chloride solution made by dissolving 5.0 grams of sodium chloride in 40.0 mL of solution?
Answer (3)
The question asks to determine the percent mass/volume of a sodium chloride solution that was made by dissolving 5.0 grams of sodium chloride in 40.0 ml of solution. To find the percent mass/volume of a sodium chloride solution, you need to divide the mass of sodium chloride by the volume of the solution and multiply by 100%. To calculate the percent mass/volume (% m/v), you use the formula:
% m/v = (mass of solute in grams/volume of solution in mL) × 100%
Substituting the given values:
% m/v = (5.0 g / 40.0 mL) × 100%
% m/v = (0.125 g/mL) × 100%
% m/v = 12.5%
Therefore, the sodium chloride solution has a percent mass/volume concentration of 12.5%.
To determine the percent mass/volume concentration of a sodium chloride (NaCl) solution, you can use the formula for mass/volume percent (m/v%). This is calculated by taking the mass of the solute (NaCl) and dividing it by the volume of the solution, then multiplying by 100% to convert it into percentage form:
% m/v = (mass of NaCl in grams / volume of solution in mL) x 100%
For the given scenario with 5.0 grams of NaCl dissolved in 40.0 mL of solution:
% m/v = (5.0 g / 40.0 mL) x 100% = (0.125 g/mL) x 100% = 12.5% m/v
Therefore, the percent mass/volume concentration of the sodium chloride solution is 12.5%.
The percent mass/volume of the sodium chloride solution is calculated to be 12.5%. This is done using the formula . Substituting 5.0 grams of NaCl in 40.0 mL of solution yields the result.
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