Stainless steel is an alloy of iron containing 5 percent nickel and 0.175 percent chromium. How many atoms of nickel are present in an 84 g sample of this alloy?
Answer in units of atoms.
Answer (3)
To find the number of nickel atoms in an 84 g sample of stainless steel with 5% nickel, you calculate 5% of the total mass to get the mass of nickel, convert that to moles using nickel's molar mass, and then multiply by Avogadro's number. The result is approximately 4.31 x 1022 nickel atoms. ;
There are approximately 4.33 x 10^{22 atoms of nickel in a 84 g sample of stainless steel alloy containing 5% nickel.
To determine how many atoms of nickel are present in a 84 g sample of stainless steel alloy containing 5% nickel, we need to follow these steps:
Step 1: Calculate the mass of nickel in the alloy.
The alloy contains 5% nickel, so we can find the mass of nickel by multiplying the total mass of the alloy (84 g) by the percentage of nickel:
Mass of nickel = 5% of 84 g = (5/100) × 84 g = 4.2 g
Step 2: Calculate the number of moles of nickel.
To do this, we need to use the atomic mass of nickel, which is approximately 58.69 g/mol.
Number of moles of nickel = Mass of nickel / Atomic mass of nickel
Number of moles of nickel = 4.2 g / 58.69 g/mol ≈ 0.0715 moles
Step 3: Calculate the number of atoms of nickel.
One mole of any substance contains Avogadro's number (6.022 x 10^{23 ) of atoms.
Number of atoms of nickel = Number of moles of nickel × Avogadro's number
Number of atoms of nickel = 0.0715 moles × 6.022 x 10^{23 atoms/mole ≈ 4.33 x 10^{22 atoms
So, there are approximately 4.33 x 10^{22 atoms of nickel in a 84 g sample of stainless steel alloy containing 5% nickel.
The complete question is here:
Stainless steel is an alloy of iron containing 5 percent nickel and 0.175 percent chromium. How many atoms of nickel are present in a 84 g sample of this alloy?
Answer in units of atoms
In an 84 g sample of stainless steel alloy with 5% nickel, the mass of nickel is 4.2 g. This corresponds to approximately 0.0715 moles of nickel, which equals around 4.33 x 10^{22} atoms. Therefore, there are approximately 4.33 x 10^{22} atoms of nickel in the sample.
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