A 2.0 kg cart moving in a straight line hits a piece of modeling clay (1.0 kg) that is at rest. The clay sticks to the cart, and both move to the left at 1.0 m/s.

What was the initial velocity of the cart and in which direction? (Remember to include - to indicate direction if necessary.)

\[ v = \]
- 1.5 m/s to the right
- 1.0 m/s to the right
- 0.5 m/s to the right
- 1.5 m/s to the left

It is 1.5 m/s to the left (1 m/s)(2 kg + 1 kg) - (1 kg)(0 m/s))/2 kg = 1.5 m/s to the left

Answered by megeliz13 | 2024-06-10

**The velocity of the cart is 1.5 m/s to the left **if the 2.0 kg cart moving in a straight line hits a piece of modeling clay (1.0 kg) that is at rest.
What is mass?
A **tangible **body's mass is the **amount **of **matter **it possesses . It's also a **metric **of **inertial **or the **resistance **to velocity when a **net force **is exerted.
We have:
A 2.0 kg cart moving in a straight line hits a piece of modeling clay (1.0 kg) that is at rest. The clay sticks to the cart and both move to the left at 1.0 m/s
By **conservation **of linear momentum :

= **[(1 m/s)(2 kg + 1 kg) - (1 kg)(0 m/s)]/2 kg **
= [3 - 0]/2
**= 1.5 m/s **(left side)
Thus, **the velocity of the cart is 1.5 m/s to the left **if the 2.0 kg cart moving in a straight line hits a piece of modeling clay (1.0 kg) that is at rest.
Learn more about the **mass **here:
https://brainly.com/question/15959704
#SPJ2

Answered by maheshpatelvVT | 2024-06-16

The initial velocity of the cart was calculated to be 1.5 m/s to the left using the conservation of momentum. By setting up the equation with the known masses and final velocity, we solved for the initial velocity. Thus, the answer is that the cart was moving at -1.5 m/s (to the left).
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Answered by maheshpatelvVT | 2024-09-30