We have z2-z(z+3)+3z. We have to remember order of operation. First operation inside the parenthesis, then multiply/divide and finaly add/subtract. Lets do this z 2 − z ( z − 3 ) + 3 z First we have to multiply -z by each argument inside the parenthesis. z 2 − z 2 + 3 z + 3 z = 6 z
Finally we can simplify z^2 with -z^2 and 3z with 3z to get the result 6z.
The expression z 2 − z ( z + 3 ) + 3 z simplifies to 0 after distributing and combining like terms. All terms cancel each other out. Therefore, the final result is 0.
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