How many grams of calcium bromide are in 50.0 mL of a 0.25 M calcium bromide solution?
Answer (3)
C_{m}=\frac{n}{V_{r}}\\\\
m=\frac{m}{M}\\\\
C_{m}=\frac{m}{MV_{r}} \ \ \ \ \Rightarrow \ \ \ \ m=C_{m}MV_{r}}\\\\
C_{m}=0.25\frac{mol}{L}\\
M_{CaBr_{2}}=200\frac{g}{mol}\\
V_{r}=50mL=0.05L\\\\
m=0.25\frac{mol}{L}*200\frac{g}{mol}*0.05L= \emph{\textbf{2.5g}}
The **mass **of the **compound **can be calculated by the molarity . The **mass **of the **calcium bromide **in the given **solution **is 2.5 g.
The **mass **of the given **compound **can be calculated by the **molarity **formula,
M = m × v w × 1000 w = 1000 M × m × v
Where,
M- molarity of the solution =** 0.25 M**
w - given **mass **=?
m -**molar mass **of Calcium bromide = 200 g/mol
v- **volume **in mL= 50 mL
Put the values in the formula,
w = 1000 0.25 × 200 × 50 w = 2.5 g
Therefore, the **mass **of the **calcium bromide **in the given **solution **is 2.5 g.
To know more about Molarity,
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In a 50.0 mL solution of 0.25 M calcium bromide, there are approximately 2.50 grams of calcium bromide. This was calculated by determining the moles from the molarity and volume and then converting that to grams using the molar mass. The molar mass of calcium bromide is approximately 199.88 g/mol.
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