Given that P-31 is the only natural isotope of phosphorus, what is the mass of one phosphorus atom and the mass of Avogadro's number of phosphorus atoms, respectively?
Answer (3)
The mass of on P atom would be 31 divided by 6.02 * 10^23 The mass of Avogadro's number of P atoms would be 31, since the atomic weight of and element is the mass of exactly one mole of that element, and Avogadro's number is the number of atoms in one mole.
Mass of Avogadro's number of P atoms = 31 g
Mass of 1 P atom = 5.15*10⁻²³ g ;
The mass of one phosphorus atom is approximately 5.15 x 10⁻²³ grams, while the mass of Avogadro's number of phosphorus atoms is 31 grams. This is based on the molar mass of the naturally occurring isotope P-31. The calculations use Avogadro's number to relate the mass of one mole to the mass of an individual atom.
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