At constant temperature, the pressure on a 6.0 L sample of a gas is reduced from 2.0 atm to 1.0 atm. What is the new volume of the gas sample?
Answer (3)
V = 12 L ;
Taking into account the Boyle's law, the new volume is 12 L .
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:
"The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"
Boyle's law is expressed mathematically as:
Pressure * Volume = constant
or P× V = k
Studying two different states, an initial state 1 and a final state 2, it is satisfied:
P1× V1= P2× V2
In this case , you know:
P1= 2 atm
V1= 6 L
P2= 1 atm
V2= ?
Replacing:
2 atm× 6 L= 1 atm× V2
Solving:
V 2 = 1 a t m 2 a t m x 6 L
V2= 12 L
In summary, the new volume is 12 L .
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The new volume of the gas sample, when the pressure is reduced from 2.0 atm to 1.0 atm, is 12.0 L. This is calculated using Boyle's Law, which states that pressure and volume are inversely related at constant temperature. Therefore, as pressure decreases, the volume of the gas increases.
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