What is the total number of electrons in the second principal energy level of a sodium atom in the ground state?

The second level has s and p orbitals, the s orbital holds two electrons and all three p orbitals also hold two each for a total of eight electrons in the second energy level.

Answered by dlpeckham | 2024-06-10

Sodium has 11 electrons, and in its ground state, 8 of these electrons are located in the second principal energy level.
The total number of electrons in the second principal energy level of a sodium atom in the ground state can be determined by understanding the electron configuration of sodium.
Sodium (Na) has an atomic number of 11, which means it has 11 electrons. In the ground state, these electrons are distributed in various energy levels. The second principal energy level, often denoted as n=2, can hold a maximum of 8 electrons. The first energy level, n=1, can hold a maximum of 2 electrons.
To find the number of electrons in the second energy level, we first fill the first energy level with 2 electrons and then place the remaining 9 electrons in the second energy level. However, since the second energy level can only hold 8 electrons, sodium's electron configuration in the ground state is 2-8-1, where 2 electrons are in the first energy level, 8 electrons are in the second energy level, and 1 electron is in the third energy level.
So, there are 8 electrons in the second principal energy level of a sodium atom in the ground state.
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Answered by robinkumar9613 | 2024-06-18

A sodium atom has a total of 8 electrons in its second principal energy level in the ground state. This is derived from its electron configuration of 1s² 2s² 2p⁶ 3s¹. The first principal energy level fills with 2 electrons, and the second level fills to its maximum of 8 electrons.
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Answered by robinkumar9613 | 2024-10-01