What is the mass of 2 moles of KBr and the mass of 0.1 moles of [tex]C_6H_{12}O_6[/tex]?

K=39g Br=79.9 (39+79.9)=237.8g
C=12 H=1g O=16g 6(12)+12(1)+6(16)=180g 237.8+180=417.8g total

Answered by apologiabiology | 2024-06-10

The mass of 2 mol of KBr is 238.00 g, and the mass of 0.1 mol of C₆H₁₂O₆ is 18.00 g.
To find the mass of a substance, you need to know the molar mass of that substance and then use the formula:

Mass (g) = Moles (mol) × Molar Mass (g/mol)


Mass of 2 mol of KBr:


The molar mass of KBr (potassium bromide) is the sum of the atomic masses of potassium (K) and bromine (Br).

From the periodic table, we find:

K: 39.10 g/mol
Br: 79.90 g/mol

So, the molar mass of KBr is:

39.10 g/mol + 79.90 g/mol = 119.00 g/mol

Now, using the formula:

Mass of KBr = 2 mol × 119.00 g/mol = 238.00 g


Mass of 0.1 mol of C₆H₁₂O₆:


The molar mass of C₆H₁₂O₆ (glucose) is calculated by summing the atomic masses of all the atoms in the formula.

Given:

C: 12.00 g/mol
H: 1.00 g/mol
O: 16.00 g/mol

The molar mass is:

(6 × 12.00 g/mol) + (12 × 1.00 g/mol) + (6 × 16.00 g/mol) = 72.00 g/mol + 12.00 g/mol + 96.00 g/mol = 180.00 g/mol

Now, using the formula:

Mass of C₆H₁₂O₆ = 0.1 mol × 180.00 g/mol = 18.00 g

Therefore, the mass of 2 mol of KBr is 238.00 g and the mass of 0.1 mol of C₆H₁₂O₆ is 18.00 g.

Answered by IanMckellen | 2024-06-25

The mass of 2 moles of KBr is 238.00 g, and the mass of 0.1 moles of C₆H₁₂O₆ is 18.02 g. To find these values, we calculated the molar masses and used the formula for mass. This involved summing atomic weights and applying basic mole calculations.
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Answered by IanMckellen | 2024-12-26