What is the mass of 0.01 mol of [tex]Na_2SO_4[/tex]?

mass of Na=22.9 grams S=32 grams O=16 2(22.99)+32+4(16)=141.98g so 141.98g=1mol of Na2SO4 so 141.98 times 0.01=1.4198 round to 3 sig figs 1.42 grams

Answered by apologiabiology | 2024-06-10

The mass of 0.01 moles of Na2SO4 can be calculated by first determining the molar mass of Na2SO4. The molar mass is the sum of the masses of all atoms in the molecule.
Using atomic masses (Na = 22.99 g/mol, S = 32.06 g/mol, O = 16.00 g/mol), we find:
2 x Na = 2 x 22.99 g/mol = 45.98 g/mol1 x S = 32.06 g/mol4 x O = 4 x 16.00 g/mol = 64.00 g/mol
Adding these together gives the molar mass of Na2SO4 as 142.04 g/mol.
To find the mass of 0.01 moles, multiply the molar mass by the number of moles:
0.01 moles x 142.04 g/mol = 1.4204 grams
Therefore, the mass of 0.01 moles of Na2SO4 is 1.4204 grams.

Answered by BurtLancaster | 2024-06-24

To find the mass of 0.01 moles of sodium sulfate (Na₂SO₄), first calculate its molar mass, which is 142.0 g/mol. Then, multiply the number of moles (0.01) by the molar mass to get a mass of 1.42 grams. Therefore, the mass of 0.01 moles of Na₂SO₄ is 1.42 grams.
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Answered by apologiabiology | 2024-09-04