Write the balanced equation for the neutralization reaction between [tex]HI[/tex] and [tex]Ba(OH)_2[/tex] in aqueous solution. Include physical states.
Answer (3)
Balanced chemical reaction: **2HI(aq) + Ba(OH)₂(aq) → BaI₂(aq) + 2H₂O(l). **
Ionic reaction: 2H⁺ + I⁻(aq) + Ba²⁺ + 2OH⁻(aq) → Ba²⁺ + 2I⁻(aq) + 2H₂O(l).
Net ionic reaction: 2H⁺ + 2OH⁻(aq) → 2H₂O(l).
Barium iodide is salt that dissolves in water, barium hydroxide is strong base that dissolves in water.
This is example of double replacement reactions(double displacement or metathesis reactions), two ionic compounds are exchanged, making two new compounds .
The balanced chemical equation for the neutralization reaction between HI and Ba(OH)2 is:
2HI(aq) + Ba(OH)₂(aq) —> BaI₂(aq) + 2H₂O(l)
Neutralization reaction is a reaction in which an acid reacts with a base to produce salt and water .
The neutralization reaction between HI and Ba(OH)₂ can be written as follow:
HI + Ba(OH)₂ —> BaI₂ + H₂O
There are** 2 atoms** of I on the right side and** 1 atom** on the left side. It can be balance by writing 2 before HI as shown below:
2 HI + Ba(OH)₂ —> BaI₂ + H₂O
There are** 2 atoms** of H on the right side and a total of 4 on the left side. It can be balance by writing 2 before H₂O as shown below:
2HI(aq) + Ba(OH)₂(aq) —> BaI₂(aq) + 2 H₂O(l)
Now the equation is balanced.
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The balanced equation for the neutralization reaction between HI and Ba(OH)₂ is 2HI(aq) + Ba(OH)₂(aq) → BaI₂(aq) + 2H₂O(l). This equation shows the reaction of 2 moles of hydrogen iodide with 1 mole of barium hydroxide to produce 1 mole of barium iodide and 2 moles of water. All compounds are in their respective aqueous or liquid states as indicated.
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