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Answer (3)
The statement at the top says that the triangles are 'similar'. That means that the corresponding angles are equal, and each pair of corresponding sides have the same ratio. From the 4 and the 8, you can see that each side in the small one is 1/2 the length of the corresponding side in the big one. So the missing sides are 1/2 the length of the 7 and the 12.
Similar triangles share the same shape due to equal corresponding angles and proportional corresponding sides. This means if you know one triangle's dimensions, you can determine the others using ratios. For example, if one triangle has sides of 3 cm, the similar triangle with twice those lengths has sides of 6 cm, demonstrating their proportional relationship.
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Materi : Limit Lim ( x → 1 )f(x) = ( x² + 2x + 1 )/( x² - 1 )---(1) Isi langsung ( x → 1 ) f(1) = ( 1² + 2[1] + 1 )/( 1² - 1 )f(1) = ( 1 + 2 + 1 )/( 1 - 1 )f(1) = 4/0 [ Tidak Terdefinisi ] ×---(2) Pemfaktoran ( x² + 2x + 1 ) → ( x + 1 )²( x² - 1 ) → ( x + 1 )( x - 1 )__________________÷f(x) = ( x + 1 )/( x - 1 )f(1) = ( 1 + 1 )/( 1 - 1 )f(1) = 2/0 [ Tidak Terdefinisi ] ×---(3) L'Hipotal [ konsep turunan ][ f(x) = xⁿ → f'(x) = n . xⁿ-¹ ]---Lim ( x → n ) f(x)/g(x) = Lim ( x → n ) f'(x)/g'(x)___________________/( x² + 2x + 1 ) → ( 2x + 2 )( x² - 1 ) → ( 2x )\/Lim ( x → 1 ) ( 2x + 2 )/2x= ( 2[1] + 2 )/( 2[1] )= ( 2 + 2 )/2= 4/2= 2Kesimpulan Limit ( x → 1 ) dari f(x) = ( x² + 2x + 1 )/( x² - 1 ) adalah 2.---Semoga bisa membantu [tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\:BLUEBRAXGEOMETRY}}}} [/tex]
