Bantu jawabHaryo memutar sebuah batu yang diikat pada seutas tali secara horizontal di atas kepalanya. Jika kecepatan linear batu dijadikan 2 kali semula, maka tentukan gaya sentripetal batu tersebut!​

x - teachers y - boys z - girls
x + y + z = 394 x + y = 189 x + z = 217 x + y + z = 394 y = 189 − x z = 217 − x x + 189 − x + 217 − x = 394 − x = − 12 x = 12 y = 189 − 12 y = 177 z = 217 − 12 z = 205

Answered by konrad509 | 2024-06-10

There are 12 teachers, 177 boys, and 205 girls at Black Horse Junior School. These numbers were determined by setting up equations based on the information given and solving for each variable. The solution involves simple algebraic manipulation.
;

Answered by konrad509 | 2024-10-23

Jawaban: F = 4mv²/rDik : Batu melakukan gerak melingkar v = kecepatan awal v' = 2vDit : Fs = ? ketika v' = 2vJwb :Percepatan sentripetala = v²/rHukum Newton 2F = m . a (gunakan a sentripetal)F = m . v²/r (persamaan gaya sentripetal)F = m . v'²/r (substitusikan nilai v')F = m . (2v)²/r F = m . 4v²/rF = 4mv²/r (jawaban)

Answered by RefiTarsudivski | 2025-07-02