Bilangan kelipatan 4 yang habis di bagi 5

y = 2 x − 3 ( 0 ; − 3 ) → x = 0 ; y = − 3 L = − 3 ; R = 2 ⋅ 0 − 3 = − 3 L = R P o in t ( 0 ; − 3 ) i s o n t h e l in e ( 1 ; 2 ) → x = 1 ; y = 2 L = 2 ; R = 2 ⋅ 1 − 3 = 2 − 3 = − 1 L  = R P o in t ( 1 ; 2 ) i s n ′ t o n t h e l in e ( 2 ; 1 ) → x = 2 ; y = 1 L = 1 ; R = 2 ⋅ 2 − 3 = 4 − 3 = 1 L = R P o in t ( 2 ; 1 ) in o n t h e l in e A n s w er : ( 0 ; − 3 ) ; ( 2 ; 1 )

Answered by Anonymous | 2024-06-10

The points on the line y = 2 x − 3 are from Option B: (0, -3) and (2, 1). The other options contain at least one point that does not satisfy the equation. Thus, B is the correct choice.
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Answered by Anonymous | 2024-12-22

Jawaban:20, dan semua kelipatan 20Penjelasan dengan langkah-langkah:bilangan kelipatan 4 yang habis dibagi 5.20, karena kelipatan 4 yakni 20 jika dibagikan 5 adalah 4. lebih jelas 20 : 5 = 4, menjadikan 20 (kelipatan 4) habis dibagikan 5.

Answered by studyfileaisyahkeifa | 2025-07-02