What You Need: Metal spoon 30 inches of kite string (40 inches for an adult) What You Do: Tie the handle of the spoon at the midpoint of the string. Wrap the ends of the string around your index fingers (pointer fingers) Place your fingers in your ears. Lean over so that spoon hangs freely and swing the spoon so it taps against a door. Hit the door again, this time harder. and you can hear it as a bell ( may be church bell sometimes )
A spoon can sound like a bell through sound vibrations that occur when it strikes another surface. By using a string to hold the spoon and tapping it against a door, the vibrations produced can resemble the ringing of a bell. This illustrates the principles of sound waves and resonance.
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✅ Jawaban:Orang kidal biasanya memiliki sifat resesif ➡️ genotipe aa Langkah-langkah:1️⃣ Hitung frekuensi aa (q²):q² = 20 ÷ 40.000 = 0,00052️⃣ Cari nilai q (akar dari q²):q = √0,0005 = 0,022363️⃣ Hitung nilai p:p = 1 - q = 1 - 0,02236 = 0,977644️⃣ Hitung frekuensi heterozigot (Aa):2pq = 2 × 0,97764 × 0,02236 = 0,04375️⃣ Hitung jumlah orang heterozigot:0,0437 × 40.000 = 1.748 orang--- Kesimpulan:Jumlah orang yang heterozigot (Aa) dalam populasi tersebut adalah sekitar 1.748 orang
Penjelasan:rumus hukum Hardy-Weinberg:p + q = 1p² + 2pq + q² = 1Ket:p = gen normalq = gen kidalp² = mewakili genotip normal homozigot (AA)2pq = mewakili genotip normal heterozigot (Aa)q² = mewakili genotip orang kidal (aa)berdasarkan soal, mencari nilai q:orang kidal (aa) = q² = 20 : 40.000 = 2 : 4.000 = 0,0005q² = 0,0005q = √0,0005 = 0,02236nilai p:p + q = 1p = 1 - qp = 1 - 0,02236 = 0,97764Normal heterozigot = 2pqjumlah penduduk normal heterozigot:2pq x total penduduk = 2 (0,97764) (0,02236) x 40.000= 0,0437 x 40.000= 1.749jadi, penduduk normal heterozigot adalah 1.749