Asam cuka, CH3COOH memiliki tetapan ionisasi (Ka)= 1,8 x 10-5. Hitung persentasr asam cuka yang terionisasi dalam larutan 0,1M!
Answer (3)
33% of 90 is equal to 29.7.
To find 33% of 90, we can use the concept of percent as a** fraction** or decimal.
Method 1: Using Percent as a Fraction
To find 33% of 90, we can express 33% as the fraction 33/100 and then multiply it by 90:
33/100 * 90
To multiply fractions, we multiply the numerators and denominators:
(33 * 90) / (100)
Multiplying the numbers:
2970 / 100
Simplifying the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 10:297 / 10
So, 33% of 90 is equal to 29.7.
Method 2: Using** Percent** as a Decimal
To find 33% of 90, we can express 33% as a decimal by dividing it by 100:
33/100 = 0.33
Then, we multiply the decimal by 90:
0.33 * 90 = 29.7
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33% of 90 can be calculated using either fractions or decimals. Both methods result in 29.7, meaning that 33% of 90 equals 29.7. This shows how to convert percentages into fractions or decimals for calculations.
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Jawaban:Penjelasan:Persentase asam cuka (CH3COOH) yang terionisasi dalam larutan 0,1 M adalah sekitar 1,34%.Langkah-langkah perhitungan:1. Rumus kesetimbangan asam lemah:Untuk asam lemah, hubungan antara konsentrasi ion hidrogen ([H+]), konstanta ionisasi asam (Ka), dan konsentrasi awal asam (M) dapat dinyatakan dengan rumus: [H+] = √(Ka * M).2. Hitung [H+]:Dengan Ka = 1,8 x 10^-5 dan M = 0,1 M, maka [H+] = √(1,8 x 10^-5 * 0,1) = √(1,8 x 10^-6) = 1,34 x 10^-3 M.3. Hitung derajat ionisasi (α):Derajat ionisasi adalah perbandingan antara konsentrasi ion yang terionisasi dengan konsentrasi awal asam. Dalam hal ini, α = [H+] / M = (1,34 x 10^-3) / 0,1 = 0,0134.4. Hitung persentase ionisasi:Persentase ionisasi adalah derajat ionisasi dikalikan 100%. Jadi, persentase ionisasi = 0,0134 * 100% = 1,34%.Jadi, persentase asam cuka yang terionisasi dalam larutan 0,1 M adalah sekitar 1,34%.
