I'm going to assume that you've done logarithms ("logs") in class before you ran into this one on homework.
3(w to the -2/3 power) + 6= 198
Subtract 6 from each side:
3(w to the -2/3 power) = 192
Take the log of each side:
log(3) -(2/3) log(w) = log(192)
Subtract log(3) from each side:
-(2/3) log(w) = log(192) - log(3) . . . notice that this side is log(192/3) = log(64)
-(2/3) log(w) = log(64)
Divide each side by -(2/3) :
log(w) = -(3/2) log(64)
Raise 10 to the power of each side:
w = (64) to the -3/2 power .
==> (A number) to the -3/2 power means 1/(the number to the +3/2 power).
==> The 3/2 power means either find the number's square root and then cube it, or else find the number's cube and then square root it.
** w = **1 / (64 to the 3/2 power) = 1 / 512 .
That's choice ' B '.
To solve for w in the equation 3(w^{-2/3}) + 6 = 198, begin by isolating the term with w, then simplify, eliminate the negative exponent, and raise both sides to the power of (3/2). The solution concludes with w = 1/512. Following these systematic steps is crucial for accuracy in algebra.
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Jawaban:20Penjelasan dengan langkah-langkah:18 16 14 19 17 15Pola dari seri angka tersebut adalah: -2, -2, +518 - 2 = 16 (angka ke-2)16 - 2 = 14 (angka ke-3)14 + 5 = 19 (angka ke-4)Mengikuti pola tersebut, kita dapat menyimpulkan:19 - 2 = 1717 - 2 = 1515 + 5 = 20