[tex] ^{3} log \: 8 + ^{3}log \: 6[/tex] mohon di bantu ya, terimakasih

-- The difference between the maximum and minimum values (9 minus -1) = 10 is double the amplitude of the sine wave, so its amplitude is 5 .
-- The distance in 'time' from the minimum to the maximum (3 minus -2) = 5 is 1/2 of the cycle, so the "wavelength" is 10 .
-- The sine 'begins' halfway between the minimum and maximum = at (1/2, 4) , and it's 'phase' is proportional to ' x/10 '.
The generic sinusoid is Y = A sin(2π x) .
We know that A = 5 . And this particular wave also has a constant of 4 added to it. Now I just have to pick my way through the argument of the sine.
Y = 4 + 5 sin [ 2π (x - 0.5)/10 ] .

Answered by AL2006 | 2024-06-25

To construct a sinusoidal function from given points, we calculate the amplitude, midline, period, and phase shift. The final equation is y = 5 sin ( 5 π ​ ( x + 2 ) ) + 4 . This equation reflects the required behavior of rising from the minimum to the maximum over specified x-values.
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Answered by AL2006 | 2024-09-26

•°• Hasil dari ³log(8) + ³log(6) adalah 4 ³log(2) + 1.[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:³log(8) + ³log(6)= ³log(2³) + ³log(2 × 3)= ³log(2³) + ³log(2) + ³log(3)= 3 ³log(2) + ³log(2) + 1= (3 + 1) ³log(2) + 1= 4 ³log(2) + 1[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]

Answered by JcyntAvrWiguna | 2025-07-04