Let's work on the left side first. And remember that the tangent is the same as sin/cos .
sin(a) cos(a) tan(a)
Substitute for the tangent:
[ sin(a) cos(a) ] [ sin(a)/cos(a) ]
Cancel the cos(a) from the top and bottom, and you're left with
[ sin(a) ] . . . . . [ sin(a) ] which is [ sin²(a) ] That's the left side .
Now, work on the right side:
[ 1 - cos(a) ] [ 1 + cos(a) ]
Multiply that all out, using FOIL:
[ 1 + cos(a) - cos(a) - cos²(a) ]
= [ 1 - cos²(a) ] That's the right side .
Do you remember that for any angle, sin²(b) + cos²(b) = 1 ? Subtract cos²(b) from each side, and you have sin²(b) = 1 - cos²(b) for any angle.
So, on the right side , you could write [ sin²(a) ] .
Now look back about 9 lines, and compare that to the result we got for the left side .
They look quite similar. In fact, they're identical. And so the identity is proven.
Whew !
Question Sin α . Cos α . Tan α = (1 – Cos α) (1 + Cos α)
Answer Left side = Sin β . Tan β
Cos β = Sin β . Sin β / Cos β + Cos β = Sin² β / Cos β + Cos² β / Cos β = 1 / Cos β = Sec β = Right side proven
We proved the identity by showing that the left-hand side simplifies to sin 2 α and the right-hand side also simplifies to 1 − cos 2 α , which is equal to sin 2 α using the Pythagorean identity. Thus, both sides are equal. Therefore, the identity is verified.
;
Jawaban:0,1Penjelasan dengan langkah-langkah:[tex]10\% = \frac{10}{100} = 0.1[/tex]