Yes, I can.
And even though you haven't asked to be shown how to do it, I'll go ahead and do that too:
Call the speed of the boat (through the water) 'B'. Call the speed of the current (the water) 'C'.
When the boat is going 'up' the river, against the current, his speed past the riverbank is (B - C).
When the boat is going 'down' the river, the same way as the current, his speed past the riverbank is (B + C).
The problem says it took him 5 hours to travel 60 km against the current. Distance = (speed) x (time) 60 km = (B - C) x (5 hours)
The problem also says it took him 3 hours to return. The distance to return is the same 60 km. The other direction is the same direction as the current, so his speed on the return is (B + C). Distance = (speed) x (time) 60 = (B + C) x (3)
Now we have two equations, so we can find 'B' and 'C'.
5B - 5C = 60 3B + 3C = 60
Multiply each side of the first equation by 3, and multiply each side of the second equation by 5:
15B - 15C = 180 15B + 15C = 300
*Add *the second equation to the first one:
30B = 480 B = 480/30 = 16 km per hour.
Subtract the second equation from the first one:
-30C = -120 C = -120/-30 = 4 km per hour.
The speed of the boat through the water (B) is 16 km per hour. The speed of the water past the riverbank is 4 km per hour.
Check:
-- When the boat is going along with the current, his speed past the riverbank is (16 + 4) = 20 km per hour. In 3 hours, he covers (3 x 20) = 60.
-- When the boat is going against the current, his speed past the riverbank is (16 - 4) = 12 km per hour. In 5 hours, he covers (5 x 12) = 60 km.
yay !
The speed of the boat in still water is 16 km/h.
The speed of the current is 4 km/h.
Step 1: Define Variables
Let b be the speed of the boat in still water (in km/h).
Let c be the speed of the current (in km/h).
Step 2: Relate Speed, Distance, and Time
We know the distance traveled upstream (against the current) is 60 km, and the total time spent traveling upstream is 5 hours. We can express this using the formula:
Speed Upstream = Distance Upstream / Time Upstream
Speed Upstream = (b - c) km/h (because the current opposes the boat's speed)
Step 3: Apply the Formula for Upstream Travel
Substitute the known values for upstream travel:
(b - c) km/h = 60 km / 5 hours
Step 4: Analyze Downstream Travel
The return trip downstream (with the current) covers the same distance (60 km) in less time (3 hours). We can express this using a similar formula:
Speed Downstream = Distance Downstream / Time Downstream
Speed Downstream = (b + c) km/h (because the current aids the boat's speed)
Step 5: Apply the Formula for Downstream Travel
Substitute the known values for downstream travel:
(b + c) km/h = 60 km / 3 hours
Step 6: Solve the System of Equations
We now have two independent equations with two unknowns (b and c). There are multiple ways to solve for them. Here, we'll use elimination.
Method 1: Elimination
Notice that adding the two equations eliminates c (current speed) because it appears with opposite signs in both equations.
Add the equations for upstream and downstream travel:
2b = 60 km / 5 hours + 60 km / 3 hours
Simplify by finding a common denominator for time (hours):
2b = (12 + 20) km / 3 hours
Combine like terms:
2b = 32 km / 3 hours
Solve for b (boat speed in still water) by dividing both sides by 2:
b = 16 km/h
Step 7: Solve for Current Speed (c)
Now that we know the boat's speed in still water (b = 16 km/h), we can substitute this value back into any of the original equations to solve for the current speed (c).
We'll use the equation for upstream travel:
(b - c) km/h = 60 km / 5 hours
Substitute b = 16 km/h:
(16 km/h - c) km/h = 60 km / 5 hours
Simplify and solve for c:
c = 16 km/h - 12 km/h
c = 4 km/h
The speed of the boat in still water is 16 km/h, while the speed of the current is 4 km/h. This is determined by setting up equations based on the distance and time taken for both upstream and downstream travel. The calculations were verified to ensure accuracy.
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