Sebuah benda memiliki energi kinetik 50 joul, dan massa 200 gr berapakah kecepatn mobil tersebut

The temperature was in the range of 10-13 on 7 of the days. Give it the weight of the middle of the range = 11.5 for 7 times = 80.5
The temperature was in the range of 14-17 on 9 of the days. Give it the weight of the middle of the range = 15.5 for 9 times = 139.5
The temperature was in the range of 18-21 on 16 of the days. Give it the weight of the middle of the range = 19.5 for 16 times = 312
The temperature was in the range of 22-25 on 22 of the days. Give it the weight of the middle of the range = 23.5 for 22 times = 517
The temperature was in the range of 26-29 on 6 of the days. Give it the weight of the middle of the range = 27.5 for 6 times = 165
Total weight for all ranges = (80.5 + 139.5 + 312 + 517 + 165) = 1,214
Total number of days = 60
Estimated mean temperature = (1,214) / (60) = 20.23°C

Answered by AL2006 | 2024-06-10

To estimate the mean temperature, we organize the temperature data into ranges, calculate midpoints for each range, multiply the midpoints by the number of days in that range, sum these products, and divide by the total number of days. The estimated mean temperature is approximately 20.23°C. This provides a clear, systematic approach to finding the mean temperature from grouped data.
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Answered by AL2006 | 2024-09-30

Jawaban:Energi kinetik (EK) dihitung dengan rumus: EK = 1/2 * m * v² di mana: - EK = energi kinetik (Joule)- m = massa (kg)- v = kecepatan (m/s) Pertama, kita konversi massa ke kilogram: 200 gram = 200/1000 kg = 0.2 kg Kemudian, kita masukkan nilai yang diketahui ke dalam rumus dan selesaikan untuk v: 50 J = 1/2 * 0.2 kg * v² 100 J = 0.2 kg * v² v² = 100 J / 0.2 kg = 500 m²/s² v = √500 m²/s² ≈ 22.36 m/s Jadi, kecepatan benda tersebut adalah sekitar 22.36 m/s.

Answered by manusiayanghidup291 | 2025-07-03