1 q u a r t er = $0.25 1 d im e = $0.10 1 ni c k e l = $0.05 q → t h e n u mb er o f t h e q u a r t ers d → t h e n u mb er o f t h e d im es → t h e n u mb er o f t h e ni c k e l s q = 2 d an d n = 3 q ⇒ n = 3 ⋅ 2 d = 6 d q ⋅ 0.25 + d ⋅ 0.10 + n ⋅ 0.03 = 1.80 2 d ⋅ 0.25 + d ⋅ 0.1 + 6 d ⋅ 0.05 = 1.8
0.5 d + 0.1 d + 0.3 d = 1.8 0.9 d = 1.8 ⇒ d = 2 ⇒ q = 2 ⋅ 2 = 4 an d n = 6 ⋅ 2 = 12 A n s . 4 q u a r t ers , 2 d im es , 12 ni c k e l s
The newspaper carrier has 4 quarters, 2 dimes, and 12 nickels. This was determined by setting up equations with the given relationships between the coins and their total value. Solving those equations leads to the final counts of each type of coin.
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Penjelasan dengan langkah-langkah:699 = 1 × 365 + 334 hariterhitung 1 tahun334 = 11 × 30 + 4 hariterhitung 11 bulan lebih 4 harimaka kesimpulan699 hari = 1 tahun 11 bulan lebih 4 hari