1 volt = 1 joule per coulomb
50 volts = 50 joules per coulomb
50 joules/coulomb times 6 coulombs = 300 joules
I = t Q W = V I t = V t Q t = V Q = 50 × 6 = 300
The electrical energy expended when moving a charge of 6 coulombs across a potential difference of 50 volts is 300 joules. This is calculated using the formula E = Q × V . Therefore, the total energy consumed is 300 J.
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DiketahuiAda 8 simbolDiambil 3DitanyaPersentase yang diambilDijawab[tex] \frac{3}{8} \div 100\% = 0.375 \times 100\% = 37.5\%[/tex]KesimpulanMaka jawabannya 37,5%