Sebuah mobil berjalan dengan kecepatan 30km/jam dalam cuaca berkabut dan dihari cuaca terang rata rata 50km/jam berapa lama waktu yang dibutuhkan untuk jarak sepanjang 210km, kalau dua pertujuh dari perjalanan itu di timpa kabut?

You always start by simplifying. 6b-49=2 ( b-3) becomes 6b-49=2b-6 From there you can group the b's together by subtracting 2b from both sides, leaving you with 4b-49=-6 Now you can get the b's alone by adding 49 (to cancel out -49) to both sides, giving you 4b=43, You're still trying to get b by itself, so what you'll do is divide both sides by 4, giving you b=10.75

Answered by historygeek96 | 2024-06-10

6 b − 49 = 2 ( b − 3 ) 6 b − 49 = 2 b − 6 4 b = 43 b = 4 43 ​

Answered by konrad509 | 2024-06-10

To solve the equation 6 b − 49 = 2 ( b − 3 ) , first distribute the right-hand side, then arrange the equation to isolate b . After simplifying, you find that b = 10.75 .
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Answered by historygeek96 | 2024-12-26

Jawaban:5 jamPenjelasan dengan langkah-langkah:[tex] \tt = \frac{2}{7} \times 210 \div 30 + (1 - \frac{2}{7} ) \times 210 \div 50[/tex][tex] \tt = \frac{420}{7} \div 30 + ( \frac{7}{7} - \frac{2}{7} ) \times 210 \div 50[/tex][tex] \tt = 60 \div 30 + \frac{5}{7} \times 210 \div 50[/tex][tex] \tt = 2 + \frac{1.050}{7} \div 50[/tex][tex] \tt = 2 + 150 \div 50[/tex]= 2 + 3 jam= 5 jam[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]

Answered by Milana01 | 2025-07-06