Bagaimana pestisida kimia di buat

0 \wedge \log_3x>0 \wedge \log_5(\log_3x)>0\\ D:x>0\wedge x>1 \wedge\log_3x>1\\ D:x>1 \wedge x>3\\ D:x>3\\ \log_5(\log_3x)=1\\ \log_3x=5\\ x=3^5\\ x=243"> lo g 2 ​ ( lo g 5 ​ ( lo g 3 ​ x )) = 0 D : x > 0 ∧ lo g 3 ​ x > 0 ∧ lo g 5 ​ ( lo g 3 ​ x ) > 0 D : x > 0 ∧ x > 1 ∧ lo g 3 ​ x > 1 D : x > 1 ∧ x > 3 D : x > 3 lo g 5 ​ ( lo g 3 ​ x ) = 1 lo g 3 ​ x = 5 x = 3 5 x = 243

Answered by konrad509 | 2024-06-10

The value of x that satisfies the equation lo g 2 ​ [ lo g 5 ​ ( lo g 3 ​ x ) ] = 0 is x = 243 . This solution also meets all required conditions for valid logarithmic values.
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Answered by konrad509 | 2025-01-20

Jawaban:Penjelasan:D. Berdasarkan asal bahan aktif, pestisida dapat digolongkan menjadi : Sintetik Anorganik : garam-garam beracun seperti arsenat, flourida, tembaga sulfat dan garam merkuri. Organik Organo khlorin : DDT, SHC, endrin, dieldrin, dll. Heterosiklik : Kepone, mirexOrganofosfat : klorpirifos, prefonofos, dll.

Answered by lakshmi12102008 | 2025-07-05