Sebuah transformator pada sisi primer 200lilitan sisi sekunder 50lilitan tegangan 120 volt berapa tegangan sisi sekunder

0\\ \sqrt{\Delta}=\sqrt{t^2+4cn}\\ x_1=\frac{-t-\sqrt{t^2+4cn}}{2\cdot(-n)}=\frac{t+\sqrt{t^2+4cn}}{2n}\\ x_2=\frac{-t+\sqrt{t^2+4cn}}{2\cdot(-n)}=\frac{t-\sqrt{t^2+4cn}}{2n}\\"> f ( x ) = − n x 2 + t x + c = 0 Δ = t 2 − 4 ⋅ ( − n ) ⋅ c = t 2 + 4 c n 1. Δ < 0 ⇒ x ∈ ∅ 2. Δ = 0 x = 2 ⋅ ( − n ) − t ​ = 2 n t ​ 3. Δ > 0 Δ ​ = t 2 + 4 c n ​ x 1 ​ = 2 ⋅ ( − n ) − t − t 2 + 4 c n ​ ​ = 2 n t + t 2 + 4 c n ​ ​ x 2 ​ = 2 ⋅ ( − n ) − t + t 2 + 4 c n ​ ​ = 2 n t − t 2 + 4 c n ​ ​

Answered by konrad509 | 2024-06-10

To solve the equation − n x 2 + t x + c = 0 , use the quadratic formula. The discriminant Δ will determine the number of solutions, resulting in no solutions, one solution, or two solutions based on its value. Solutions can be calculated using specific formulas derived from the discriminant and coefficients of the equation.
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Answered by konrad509 | 2025-05-10

Jawaban:Vs = 30 voltPenjelasan:Diketahui:Np = 200 lilitanNs = 50 lilitanVp = 120 voltDitanya:Vs....?Jawab:[tex]\frac{Vp}{Vs} =\frac{Np}{Ns}=\frac{Is}{Ip}[/tex][tex]\frac{120}{Vs}=\frac{200}{50}[/tex]200Vs = 120 x 50Vs = [tex]\frac{6000}{200}[/tex]Vs = 30 volt

Answered by Sunariyadi | 2025-07-05