Bila daya pada peralatan 10 kw dialiri Arus 5 amper, Tahan 2 Ω Berapa tegangannya ?
Answer (4)
To find the equation of a quadratic function with given zeros, we can use the formula f(x) = a(x - a)(x - b), where a and b are the zeros. For x=2 and x=-5, the equation is f(x) = (x-2)(x+5), which can be expanded to f(x) = x^2 + 3x - 10. ;
The quadratic function with zeros at x = 2 and x = -5 is f(x) = (x - 2)(x + 5).
f(x) = x² + 3x - 10.
First, write the function in factored form:
f(x) = (x - 2)(x + 5)
Next, expand this product to find the standard form,
*f(x) = (x - 2)(x + 5) = x 2 + 5 x − 2 x − 10 * = x 2 + 3 x − 10
Therefore, the equation of the quadratic function in standard form is:
f(x) = x² + 3x - 10
The equation of the quadratic function with zeros at x = 2 and x = − 5 can be expressed in standard form as f ( x ) = x 2 + 3 x − 10 . This was determined by expanding the factored form of the quadratic function. Combining like terms gave us the standard expression for the quadratic function.
;
•°• Bila daya peralatan 10 kW dialiri arus 5 ampere dan ketahanan 2 Ω. Tegangannya adalah 2.000 volt dan 2 kilo Volt.[tex] \\ \\ [/tex]Penjelasan:1 kw = 1.000 w1 kV = 1.000 volt [tex] \: [/tex]Daya (P) = 10 kW = 10.000 WArus (I) = 5 AResistansi (R) = 2 ΩTegangan (V) = ?[tex] \: [/tex]V = P/IV = 10.000 W/5 AV = 2.000 volt atau 2 kilo Volt[tex] \: [/tex]•°• Jadi, tegangnya adalah 2.000 volt atau 2 kilo Volt.[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]
