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Hello!
An antacid tablet containing 0.50 g of NaHCO3 is dissolved in 250 mL of water. What is the molar concentration of NaHCO3 in the solution ?

We have the following data:

M (Molar Concentration or Molarity) = ? (in mol/L)
m (mass) = 0.50 g
V (volume) = 250 mL → 0.25 L
MM (Molar Mass of NaHCO3)
Na = 1*(23u) = 23 u
H = 1*(1u) = 1 u
C = 1*(12u) = 12 u
O = 3*(16u) = 48 u

MM (Molar Mass of NaHCO3) = 23 + 1 + 12 + 48 = 84 g/mol

We apply the data found to the formula of molar Concentration or Molarity, let's see:

M = MM ∗ V m ​
M = 84 ∗ 0.25 0.50 ​
M = 21 0.50 ​
M = 0.023809... → M ≈ 0.024 m o l / L ​ ​ ✓
Answer:
The Molar Concentration is approximately 0.024 mol/L

I Hope this helps , greetings... Dexteright02 ! ⌣ ¨

Answered by dexteright02 | 2024-06-13

1 mole of NaHCO3 = 84g
1 mole of NaHCO3--------------84g x moles of NaHCO3----------0,50g x = 0,00595 moles of NaHCO3
0,00595 moles of NaHCO3----------in--------250ml x moles of NaHCO3-------------------in-----------1000ml x = 0,0238 moles of NaHCO3
answer: the molar concentration of NaHCO3 is 0,0238mol/l

Answered by pyromorphite | 2024-06-25

The molar concentration of NaHCO₃ in the solution is 0.0238 mol/L, calculated by converting the mass of NaHCO₃ to moles and then dividing by the volume of the solution in liters.
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Answered by pyromorphite | 2024-09-27

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Answered by zahsy1114 | 2025-07-05